Coding Problem: Final Array State After K Multiplication Operations I - Easy

Difficulty: Easy

Topics: Arrays, Algorithms, Coding Challenges

Problem Description

You are given an integer array nums, an integer k, and an integer multiplier.

You need to perform k operations on nums. In each operation:

1. Find the minimum value x in nums. If there are multiple occurrences of the minimum value, select the one that appears first.
2. Replace the selected minimum value x with x * multiplier.

Return an integer array denoting the final state of nums after performing all k operations.

Examples

Example 1

Input:

nums = [2,1,3,5,6], k = 5, multiplier = 2

Output:

[8,4,6,5,6]

Explanation:

Operation	Result
After operation 1	[2, 2, 3, 5, 6]
After operation 2	[4, 2, 3, 5, 6]
After operation 3	[4, 4, 3, 5, 6]
After operation 4	[4, 4, 6, 5, 6]
After operation 5	[8, 4, 6, 5, 6]

Example 2

Input:

nums = [1,2], k = 3, multiplier = 4

Output:

[16,8]

Explanation:

Operation	Result
After operation 1	[4, 2]
After operation 2	[4, 8]
After operation 3	[16, 8]

Constraints

• 1 <= nums.length <= 100
• 1 <= nums[i] <= 100
• 1 <= k <= 10
• 1 <= multiplier <= 5

Approach

The problem can be solved using the following steps:

1. Iterate through the array k times.
2. In each iteration, find the minimum element in nums. If multiple elements are equal, select the first one.
3. Replace the selected minimum element with minimum * multiplier.
4. Return the updated array after completing all iterations.

Conclusion

This problem is a straightforward implementation challenge that tests your ability to work with arrays, loops, and conditionals. It emphasizes finding and updating specific elements in an array iteratively.

Written by CodeToCareer

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